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2009
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April
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- The importance of peer-to-peer discussion
- What we did on Thursday, wave packet propagation I
- Quiz solution
- Reading, for this week, next month..., and a question
- Electron states in crystals
- Regarding Measurement
- Key Dates: Quiz, April 28; Midterm, May 7; HW#5 du...
- Homework #4 Solutions, 7-13, see earlier posts for...
- Homework #5, due Friday, 4:30 PM
- Homework #4 discussion related to non-local states
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- Key dates: Quiz, Midterm and HW
- Extending HW, Midterm date
- Class Preview: effect of a+ on |n>
- Misc. Class notes I: State function, H.O. ground s...
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- Homework #4, final version, Due Friday 4 PM *
- Ground states
- TA Office Hours by appointment
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- Section Tonight at 6:00 PM in ISB 231
- Outline and road map for 139a:
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April
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For 10a is not the matrix we need to get back (a, b, c, d) not (1, 1, 1, 1)?
ReplyDeleteRight, but this form/factorization just shows (easily, I hope) that there is an eigenvector when a=b=c=d=1. To get more general I think there is no choice but to do the usual: solve the characteristic equation, solve for the eigenvectors.
ReplyDelete